Write a large number in standard form
Write \(583000\) in standard form.
Move the decimal point 5 places left:
\[583000=5.83\times10^5\]Answer: \(\boxed{5.83\times10^5}\)
Write very large and very small numbers efficiently using powers of 10, then calculate accurately with standard-form values.
Subtopic 1
Standard form is used to make very large and very small numbers easier to write and calculate with.
where \(1\le A<10\) and \(n\) is a positive or negative integer.
The first factor must satisfy \(1\le A<10\); rewrite anything like \(34 imes10^5\) as \(3.4 imes10^6\).
Important: In standard form, the coefficient may equal 1 but must be less than 10. The exponent can be zero, positive or negative.
Write \(583000\) in standard form.
Move the decimal point 5 places left:
\[583000=5.83\times10^5\]Answer: \(\boxed{5.83\times10^5}\)
Write \(0.0000472\) in standard form.
Move the decimal point 5 places right to obtain 4.72. Because the original number is smaller than 1, the index is negative.
\[\boxed{4.72\times10^{-5}}\]Write \(6.04\times10^{-4}\) as an ordinary number.
The power is \(-4\), so move the decimal point 4 places left:
\[6.04\times10^{-4}=\boxed{0.000604}\]Write 38.6 million in standard form.
38.6 million = 38 600 000.
\[38\,600\,000=\boxed{3.86\times10^7}\]Write \(0.000000708\) in standard form, then give \(8.15\times10^6\) as an ordinary number.
Move the point seven places to the right to get 7.08.
\[0.000000708=\boxed{7.08\times10^{-7}}\]
For the second number move the point six places to the right.
\[8.15\times10^6=\boxed{8\,150\,000}\]
Try each question before opening its worked solution.
Write \(92\,000\) in standard form.
Move the point four places left.
\[\boxed{9.2\times10^4}\]
Write \(0.0000432\) in standard form.
Move the point five places right; use a negative index.
\[\boxed{4.32\times10^{-5}}\]
Write \(3.06\times10^{-4}\) as an ordinary decimal, then compare it with \(0.00031\).
\(3.06\times10^{-4}=0.000306\).
Since \(0.000306<0.000310\),
\[\boxed{3.06\times10^{-4}<0.00031}\]
Subtopic 2
For multiplication and division, work with the number parts and powers of 10 separately. For addition and subtraction without a calculator, the source method changes the values to ordinary numbers first.
For products or quotients, use index laws; for sums/differences align place values (or powers of 10), then normalise.
Work out \((3\times10^4)(2\times10^3)\).
Work out \((6\times10^5)(4\times10^3)\). Give the answer in standard form.
24 is too large for the coefficient, so rewrite:
\[24\times10^8=\boxed{2.4\times10^9}\]Work out \((8.4\times10^7)\div(2.1\times10^3)\).
Work out \((3.6\times10^5)\div(6\times10^{-2})\). Give the answer in standard form.
The coefficient 0.6 is too small for standard form:
\[0.6\times10^7=\boxed{6\times10^6}\]For the method used in this chapter, convert each value to an ordinary number, add or subtract carefully, then convert the result back to standard form.
Work out \((5\times10^3)+(2.4\times10^4)\).
Work out \((6.2\times10^{-3})-(7.5\times10^{-4})\).
Work out \((4.5\times10^3)^2\). Give the answer in standard form.
Normalise:
\[20.25\times10^6=\boxed{2.025\times10^7}\]Calculate \(\frac{(6\times10^{-4})(3\times10^7)}{9\times10^2}\) in standard form.
Combine numerical parts: \(6\times3\div9=2\).
Combine powers: \(10^{-4+7-2}=10^1\).
\[\boxed{2\times10^1}\]
Scientific calculators usually have an EXP, EE or \(\times10^x\) style key for standard-form entry. Learn which key your calculator uses and read the displayed exponent carefully.
Ask: “Is the coefficient at least 1 and less than 10?” If not, move the decimal point and adjust the power of 10.
Try each question before opening its worked solution.
Calculate \((4\times10^3)(5\times10^2)\) in standard form.
\(4\times5=20\); powers give \(10^5\).
\[20\times10^5=\boxed{2\times10^6}\]
Work out \((8\times10^{-3})\div(2\times10^2)\).
\(8\div2=4\), power \(-3-2=-5\).
\[\boxed{4\times10^{-5}}\]
A laboratory combines \(3.5\times10^{-4}\text{ L}\) and \(7.2\times10^{-5}\text{ L}\). Give the total volume in standard form.
Write both with the same exponent:
\[3.5\times10^{-4}+0.72\times10^{-4}=4.22\times10^{-4}\]
\[\boxed{4.22\times10^{-4}\text{ L}}\]
Begin with conversions, then move to calculations and mixed exam-style problems. Keep each answer hidden until you have attempted the question.
Write in standard form: a) 7200 b) 684000 c) 39 500 000.
a) \(7200=\boxed{7.2\times10^3}\)
b) \(684000=\boxed{6.84\times10^5}\)
c) \(39\,500\,000=\boxed{3.95\times10^7}\)
Write in standard form: a) 0.0042 b) 0.000071 c) 0.000000608.
a) \(\boxed{4.2\times10^{-3}}\)
b) \(\boxed{7.1\times10^{-5}}\)
c) \(\boxed{6.08\times10^{-7}}\)
Write as ordinary numbers: a) \(3.7\times10^4\) b) \(9.02\times10^6\) c) \(5.6\times10^{-3}\) d) \(2.41\times10^{-5}\).
a) \(\boxed{37000}\)
b) \(\boxed{9\,020\,000}\)
c) \(\boxed{0.0056}\)
d) \(\boxed{0.0000241}\)
Rewrite each correctly in standard form: a) \(32\times10^5\) b) \(0.7\times10^8\) c) \(15.4\times10^{-6}\) d) \(0.09\times10^{-3}\).
a) \(32\times10^5=\boxed{3.2\times10^6}\)
b) \(0.7\times10^8=\boxed{7\times10^7}\)
c) \(15.4\times10^{-6}=\boxed{1.54\times10^{-5}}\)
d) \(0.09\times10^{-3}=\boxed{9\times10^{-5}}\)
Work out \((4\times10^6)(3\times10^2)\). Give the answer in standard form.
Work out \((7\times10^{-4})(5\times10^{-3})\).
Work out \((9\times10^8)\div(3\times10^4)\).
Work out \((2.4\times10^3)\div(8\times10^{-2})\).
Work out \((3.2\times10^5)+(4.7\times10^4)\).
Work out \((8.1\times10^{-3})-(6.4\times10^{-4})\).
A country has a population of 52.8 million. Write this population in standard form.
52.8 million = 52 800 000.
\[52\,800\,000=\boxed{5.28\times10^7}\]A thickness is \(0.0000000345\) m. Write it in standard form.
Move the decimal point 8 places right:
\[\boxed{3.45\times10^{-8}\text{ m}}\]A square has side length \(3.2\times10^4\) cm. Find its area in \(\text{cm}^2\), giving the answer in standard form.
Work out \(\dfrac{(6\times10^7)(2.5\times10^{-3})}{3\times10^2}\). Give your answer in standard form.
Numerator:
\[(6\times2.5)\times10^{7-3}=15\times10^4\]Now divide:
\[\frac{15\times10^4}{3\times10^2}=5\times10^2\]\(\boxed{5\times10^2}\)
A student writes \((8\times10^5)(4\times10^3)=32\times10^8\) and stops. Explain what is incomplete and give the final answer in standard form.
The multiplication is numerically correct, but 32 is not an allowed standard-form coefficient.
\[32\times10^8=\boxed{3.2\times10^9}\]Find \((7.4\times10^{-5})-(2.85\times10^{-5})\), giving the answer in standard form.
I check that the coefficient satisfies \(1\le A<10\).
I can move accurately between ordinary numbers and powers of 10.
I use positive powers for large values and negative powers for small positive values below 1.
I calculate coefficients and powers separately, then normalise.
I can safely convert to ordinary numbers before combining values.
I never leave answers such as \(24\times10^7\) or \(0.6\times10^5\) as standard form.
Illustrations are taken only from actual Chapter 8 diagrams where present; explanations and practice questions are newly written. Text-only book pages are not reproduced as images.